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iOS Swift 2.0 Functions Function Parameters Function Parameters

Function for named parameter

What's wrong with this? It works in playground, but not in the challenge.

Challenge Task 2 of 2

Now that we have a working function let's use it.

Call the function and pass in a value of 10 for the first parameter and 3 for the second.

Assign the result of the function operation to a constant named result.

/Users/mattconway/Desktop/Screen Shot 2016-01-18 at 3.58.29 PM.png

functions.swift
// Enter your code below
func getRemainder(value a: Int, divisor b: Int) -> Int {
return a % b
getRemainder(value:0, divisor:0)
}
let results = getReminder(value: 10, divisor: 3)

2 Answers

Hi Matt,

I'm answering this on my phone so I have a restricted view. Apologies.

I'm not sure why you are calling your getRemainder function from inside itself; I'd delete that line.

And outside the function, you've called a function called getReminder; I'd change that too. Typo! :-)

Let me know how you get on. I hope that helped.

Steve.

Nathan Tallack
Nathan Tallack
22,160 Points

You were close. Consider your fixed code below with the comments inline.

// Enter your code below
func getRemainder(value a: Int, divisor b: Int) -> Int {
  return a % b
  // No need for this last line in your function.
}

// Constant is to be named result not results
// You had a typo in your function name.  Missing the "a".
let result = getRemainder(value: 10, divisor: 3)

Keep up the good work! :)

Ryan Rassoli
Ryan Rassoli
3,365 Points

Why are your not putting value a and divisor b in the result?