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Tuan Zen
Tuan Zen
6,882 Points
Posted by Tuan Zen
Tuan Zen
6,882 Points

getDisplayName with proper case

How do I change SONY to Sony here? the method .toLowerCase() doesnt seem to work

com/example/model/Brand.java 
package com.example.model;

public enum Brand {
  JVC,
  SONY,
  COBY,
  APPLE;

  private String displayName;

  private Brand()  {}
  Brand(String displayName) {
    displayName = displayName.toLowerCase();
  }


  public String getDisplayName() {
    return displayName;
  }

}

2 Answers

Kourosh Raeen
Kourosh Raeen
23,733 Points
Kourosh Raeen
Kourosh Raeen
23,733 Points

Hi Tuan - The constructor expects a display name passed in so change

public enum Brand {
  JVC,
  SONY,
  COBY,
  APPLE;

to

public enum Brand {
  JVC("JVC"),
  SONY("Sony"),
  COBY("Coby"),
  APPLE("Apple");

Also, in the constructor the parameter name and the private member variable have the same name, so either change the member variable name to mDisplayName or use the this keyword:

package com.example.model;

public enum Brand {
  // Your code here
  JVC("JVC"),
  SONY("Sony"),
  COBY("Coby"),
  APPLE("Apple");

  private String displayName;

  private Brand()  {}
  Brand(String displayName) {
    this.displayName = displayName;
  }

  public String getDisplayName() {
    return displayName;
  }
}
Alexander Nikiforov
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Alexander Nikiforov
Java Web Development Techdegree Graduate 22,175 Points
Alexander Nikiforov
.a{fill-rule:evenodd;}techdegree seal-36
Alexander Nikiforov
Java Web Development Techdegree Graduate 22,175 Points

I think this line is wrong: displayName = displayName.toLowerCase(); In constructor if names of argument "Brand (String displayName)" and member "private String displayName" variable are the same, you have to use this keyword: this.displayName = displayName.toLowerCase();