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PHP Build a Simple PHP Application Wrapping Up The Project Objects

Help - Challenge task 3 of 7

This third-party library gives you access to create a PalprimeChecker object. Create a variable called $checker and assign it a new PalprimeChecker object as the value.

Bummer! It looks like you have not created a variable named $checker....


$checker -> $palprimechecker;

echo "The number ## ";
echo "(is|is not)";
echo " a palprime.";


1 Answer

Andrew Dushane
Andrew Dushane
9,264 Points

To create an instance of a class you use the new keyword.

$checker = new PalprimeChecker();

ought to do it.

Check out http://php.net/manual/en/language.oop5.basic.php

Thank you