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Start your free trialAtul Varma
4,285 PointsHelp with the .split() and .join()
Question: Combine the sundaes list into a new variable named display_menu, where each item in the list is rejoined together by a comma and a space (", "). Then reassign the menu variable to use the existing variable and .format() to replace the placeholder with the new string in display_menu. If you're really brave, you can even accomplish this all on the same line where menu is currently being set.
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes = available.split(';')
display_menu= ', '.join(sundaes)
menu = "Our available flavors are:{}.".format(', '.join(display_menu))
1 Answer
Andrew Mlamba
15,642 PointsHi Atul,
Looking at your code, each item in the list (sundaes) is already rejoined together by a comma and a space (", ") and assigned to the display_menu variable. So, there is no need to use the .join() method again when assigning to the menu variable. Just format the string with the display_menu
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes = available.split(';')
display_menu= ', '.join(sundaes) # <-- already rejoined
menu = "Our available flavors are:{}.".format(', '.join(display_menu)) #<-- no need to use the .join() method here
When this works, try to accomplish this all on the same line where menu is currently being set.
Atul Varma
4,285 PointsAtul Varma
4,285 PointsI did it but again tge error says task 1 is no longer passing
Atul Varma
4,285 PointsAtul Varma
4,285 PointsSorry. It works now. Thanks a lot.
Andrew Mlamba
15,642 PointsAndrew Mlamba
15,642 PointsOk. just paste your code here. The corrected version