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Python Python Basics (2015) Letter Game App Even or Odd Loop

Reine Alice
Reine Alice
2,500 Points

Hi I can not understand why my code is running.

I also do not understand this line: return not num % 2

even.py
import random
start = 5
while start:
    new_num = random.randint(1,99)
    even_odd(new_num)
    start = start -1

def even_odd(num):
    # If % 2 is 0, the number is even.
    if num % 2 == 0: 
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

1 Answer

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,258 Points

you don't need to modify the even_odd function at all in this challenge. the comments explain what is going on - if a number % 2 is 0, the number is even, but 0 in python is false, so when you call the function on an even number, you would get an answer of false, which we don't want, so we invert it with not to say 1 or true if even, and 0 or false if odd.