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Python Python Basics (2015) Logic in Python Try and Except

Posted by Jovi G.
Jovi G.
2,001 Points

Hi, I've passed the task 1 and 2. Task 3 gives me the error msg "It looks like Task 2 is no longer passing." Help please

...python

def add(a, b): try: a = int(a) b = int(b) except ValueError: return None else: a = float(a) b = float(b) return a + b ......... Is there anything wrong with this code? I dont seem to find it. A little tip will be very helpful Thank you

trial.py 
def add(a, b):
    try:
        a = int(a)
        b = int(b)
    except ValueError:
        return None
    else:
        a = float(a)
        b = float(b)
        return a + b

2 Answers

Stuart Wright
Stuart Wright
41,118 Points
Stuart Wright
Stuart Wright
41,118 Points

'Task 1 is no longer passing' usually means a syntax error, but in this case it actually doesn't. There's no syntax error in your code.

But your logic isn't quite right. You don't want to convert floats that you pass in to type integer. The changes you have to make are as follows:

  • inside your try: block, convert to float rather than int
  • remove the float conversion from your else: block
Aiden Colley
Aiden Colley
926 Points
Aiden Colley
Aiden Colley
926 Points

What it means is that you have a syntax error somewhere that python doesn't understand. I'm not sure what the syntax error is but maybe if you try changing what kind of error your trying to catch.

Jovi G.
Jovi G.
2,001 Points

Thanks for your suggestion and you were right!. I misunderstood the problem. I changed the type conversion in the "try block" and only return "the result" in the else block. It worked!! ^.^