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Python Python Collections (2016, retired 2019) Dictionaries Word Count

"Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace! " ?

what's wrong with my solution ?

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(seq):
    words = seq.lower().split(' ')
    dict = {}
    for word in words:
        dict[word] = 0
    for word in words:
        dict[word]+= 1
    return dict

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You're doing great, and my guess is that you've tried some test data. I'm also guessing that your test data isn't really comprehensive. Have you tried a string with any tabs or newline characters? :smiley:

The challenge asks that you split on all whitespace. Currently, you are only splitting on spaces. Tabs and newlines are also whitespace.

#This splits on spaces
split(' ')
#This splits on all whitespace
split()

Removing the arguments from the split() function causes it to split on all whitespace.

Hope this helps! :sparkles:

nakalkucing
nakalkucing
12,964 Points

Thanks I was having trouble with this too. : )