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Java Java Basics Perfecting the Prototype Looping until the value passes

Maati Grouni
Maati Grouni
2,481 Points
Posted by Maati Grouni
Maati Grouni
2,481 Points

I am having a problem with a do while loop to print out a string with a variable

does any one can tell me how to print out a string with a variable inside do while loop that I'm having trouble with thanks

Example.java 
// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
do {
  response = console.readLine("Do you understand do while loops?");

    console.printf("Because you said<response>, you passed the test!");

}while(response.equalsIgnoreCase("No"));

1 Answer

andren
andren
28,558 Points
andren
andren
28,558 Points

When printing a string with printf you can place a %s placeholder within the string which will be replaced with a string you pass in as the second argument to the printf method. Like this:

console.printf("Because you said %s, you passed the test!", response);

The challenge wants the message to be printed out after the loop runs though, not within the loop. So you need to place the printf statement below the loop. Like this:

String response;
do {
  response = console.readLine("Do you understand do while loops?");
} while(response.equalsIgnoreCase("No"));

console.printf("Because you said %s, you passed the test!", response);