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PHP Build a Basic PHP Website (2018) Listing and Sorting Inventory Items Review Basics

Posted by Jonas Støvring
Jonas Støvring
5,229 Points

I cant solve this one

It tells me that task 1 is no longer valid ...

output.php 
<?php
include "flavor.php";
$flavor = get_flavor;
return "$flavor";
echo "Randy's favorite flavor of ice cream is ____.";

?>

1 Answer

Adam N
Adam N
70,280 Points 
return "$flavor";

It says that task 1 is no longer valid because you have have a syntax error on the above line that clobbers the program. You cannot use the return keyword outside of a func

To save the result of a function call (without arguments) to a variable the syntax is like this:

$varName = funcName();
Jonas Støvring
Jonas Støvring
5,229 Points

Thank you