Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Python Basics (2015) Letter Game App Even or Odd Loop

seong lee
seong lee
4,503 Points

I did every thing riiiiiiiiiiiiiiiiiiiiiiiiiiiiiight

this keeps saying "Oops! It looks like Task 1 is no longer passing."

import random
start = 5

def even_odd(num):
    return not num % 2

while start > 0:
    num = random.randint(1,99)
    if even_odd(num) == False
        print ("{} is odd".format(num))
        print ("{} is even".format(num))
    start -= 1

    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.

2 Answers

Gregorio Bernabel
Gregorio Bernabel
3,412 Points

have the while loop go over start

  1. while start:
  2. and remember it wants you to have start be falsey, its already falsey so in the if statement you need to fix that with evaluating even_odd with num. dont forget your colon
Ryan S
Ryan S
27,276 Points

HI Seong,

Yes you did everything correct except for one small syntax error... you forgot a colon after your if statement.