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Start your free trialjp28
3,413 PointsI don´t understand how i'm supposed to do this task.
i´ve been trying for a while but i can´t find out how to do it, please someone tell what do i have to do.Please don´t give me any answers. Thank you Nicolas
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dict):
count = 0
for key in dict.keys():
count += 1
return count
def num_courses(dict):
count = 0
for value in dict.values():
count += len(value)
return count
def courses(dict):
names = []
for value in dict.values():
names.append(value)
names = sum(names, [])
return names
def most_courses(dict):
1 Answer
Steven Parker
231,269 PointsGood attitude. I only give hints anyway.
So here's a few:
- the instructions already suggested you might need a "max count" variable
- you might also need a "teacher with most" variable
- you might use a loop to go through the items in the dictionary
- for each item, if the course count is larger than the stored "max", you could update the max and the teacher
- then when the loop ends, you could return the last saved teacher
jp28
3,413 PointsThank you, it worked
Suwijuk Nawaphanarat
2,103 PointsHello, Mr Steven.
I managed to find the max count of the courses. However, I cannot return with a teacher name with the most courses. Here are my codes:
def most_courses(courses): most_courses = [] for key in courses.keys(): most_courses.append(len(courses[key])) return max(most_courses)
Can you please help me? Thanks!
Steven Parker
231,269 PointsTake another look at the hints I gave to Nicolás, plus:
- you won't need to create a new list
- you only need to save the largest count seen and the teacher that goes with it
- after the loop you will return the teacher
Suwijuk Nawaphanarat
2,103 PointsOh, I see. Thanks, Mr Steven!
jp28
3,413 Pointsjp28
3,413 PointsThis is what i have to do:
Create a function named most_courses that takes our good ol' teacher dictionary. most_courses should return the name of the teacher with the most courses. You might need to hold onto some sort of max count variable.