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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Aayush Mitra
Aayush Mitra
24,904 Points

I don't know what it means by Wrong number of prints.

I do not understand why it keeps on saying Wrong number of prints. Can someone please help me? Thank you!

even.py 
import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start == True:
    start -= 1
    a = random.randint(1,99)
    if even_odd(a):
        print("{} is even").format(str(a))
    else:
        print("{} is odd").format(str(a))

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,423 Points

While start is "truthy" it is not be equivalent to True, therefore the while will never exit regardless of the value of start. Instead, simply refer to the "value" of start. When start is 0, then it will be interpreted as "false" (but still not equivalent to False"):

while start:

Also, the format() method is part of the string. It should immediately follow the string. Remove the closing paren between the string and the .format method.

Post back if you have more questions. Good Luck!!

Aayush Mitra
Aayush Mitra
24,904 Points

Thank you so much.