I don't understand how I can do it. How do I put 'swallow' instead of 1... or I am thinking bad about the task?

Hi Alex

this is how i did it

# combo(['swallow', 'snake', 'parrot'], 'abc')
# Output:
# [('swallow', 'a'), ('snake', 'b'), ('parrot', 'c')]
# If you use list.append(), you'll want to pass it a tuple of new values.
# Using enumerate() here can save you a variable or two.

def combo(my_list,my_string):
  output_list=[]
  counter = 0
  for letter in my_string:
    output_list.append((my_list[counter],letter))
    counter+=1
  return output_list  

print(combo(['swallow', 'snake', 'parrot'], 'abc'))

In my combo function line1 I -> declared a list of my own to hold the output tuple line 2 -> I created a counter that will help us access the values in the list passed to the function, note this will only work if the size of the list is the same as the length of the second argument my_string. line 3 -> i loop over the string to get each letter and append it to the second half of the tuple, note i did not loop over the list as i have this counter variable to access the values in it see line4. line5-> increment the counter by 1 each time it goes around the loop.

hope this helps.