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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Amanpreet Johal
Amanpreet Johal
2,601 Points

I don't understand what I am doing wrong ?

I am not sure what part of this is wrong

even.py 
import random 
start = 5
while start : 
    def even_odd(num) :
        return not num % 2
        num = random.randint(1,99)
        if num % 2 == 0 : 
            print ("{} is even.".format(num))
        else : 
            print ( "{} is odd.".format(num))
    start -= 1 

    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.

1 Answer

Oliver Small
Oliver Small
12,578 Points
Oliver Small
Oliver Small
12,578 Points

you are putting the even_odd function within the while loop where as it should be before it. you also need to indent your start -=1.

import random 

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start: 
        num = random.randint(1,99)
        if even_odd(num):
            print ("{} is even.".format(num))
        else : 
            print ( "{} is odd.".format(num))
        start -= 1
Amanpreet Johal
Amanpreet Johal
2,601 Points

This may sound like a stupid question, why didn't it work with the function in the while loop?