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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Serious Programmer
Serious Programmer
2,650 Points
Posted by Serious Programmer
Serious Programmer
2,650 Points

I get the following error , when completing task two.

Bummer: Hmmm. It doesn't look like you're storing the returned value in the echo variable. I ran this code in the console and it worked fine. code function returnValue(drink){ var echo = drink; return echo; }

returnValue("go");

script.js 
function returnValue(print){
  var echo = print;
  return echo;
}

returnValue("go");
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

1 Answer

Adam Beer
Adam Beer
11,314 Points
Adam Beer
Adam Beer
11,314 Points

Hi Ahmir! After your newly created returnValue function, create a new variable named echo. New variable echo equal to returnValue(param). Like this.

Challenge Task 2 of 2

After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results from calling the returnValue function. When you call the returnValue function, make sure to pass in any string you'd like for the parameter.

The function will accept the string you pass to it and return it back (using the return statement). Then your echo variable will be set with what is returned, the results.

function returnValue(print){
  var echo = print;
  return echo;
}

var echo = returnValue("Good Job");

Hope this help.