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Start your free trialJacqueline Yeung
592 PointsI have document.querySelectorAll('a.className'); What am I doing wrong?
I believe I am doing this right.
const navigationLinks = document.querySelectorAll('li.george');
let galleryLinks;
let footerImages;
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Nick Pettit | Designer</title>
<link rel="stylesheet" href="css/normalize.css">
<link href='http://fonts.googleapis.com/css?family=Changa+One|Open+Sans:400italic,700italic,400,700,800' rel='stylesheet' type='text/css'>
<link rel="stylesheet" href="css/main.css">
<link rel="stylesheet" href="css/responsive.css">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
</head>
<body>
<header>
<a href="index.html" id="logo">
<h1>Nick Pettit</h1>
<h2>Designer</h2>
</a>
<nav>
<ul>
<li class="george"><a href="index.html" class="selected choice">Portfolio</a></li>
<li class="george"><a href="about.html" class="choice">About</a></li>
<li class="george"><a href="contact.html" class="choice">Contact</a></li>
</ul>
</nav>
</header>
<div id="wrapper">
<section>
<ul id="gallery">
<li>
<a href="img/numbers-01.jpg">
<img src="img/numbers-01.jpg" alt="">
<p>Experimentation with color and texture.</p>
</a>
</li>
<li>
<a href="img/numbers-02.jpg">
<img src="img/numbers-02.jpg" alt="">
<p>Playing with blending modes in Photoshop.</p>
</a>
</li>
</ul>
</section>
<footer>
<a href="http://twitter.com/nickrp"><img src="img/twitter-wrap.png" alt="Twitter Logo" class="social-icon"></a>
<a href="http://facebook.com/nickpettit"><img src="img/facebook-wrap.png" alt="Facebook Logo" class="social-icon"></a>
<p>© 2016 Nick Pettit.</p>
</footer>
</div>
<script src="js/app.js"></script>
</body>
</html>
1 Answer
Steven Parker
231,269 PointsYou say your code should have 'a.className'
as the selector, but what is shown in the code above is 'li.george'
!
But neither of those are what the challenge is asking for. The challenge says "select all links in the nav element". Remember that links are represented by anchor ("a") elements, and to select something that is "in" another thing you would probably want a descendant selector (where the two things are separated by a space).
Jacqueline Yeung
592 PointsJacqueline Yeung
592 Pointsthanks! got it.