I revised it however still a problem

Question

def members(dict,list):
    count=0
    for item in list:
        if bool(dict[item])==True:
            count=count+1
        else:
            count=count
    return count
```counts.py
You can check for dictionary membership using the
"key in dict" syntax from lists.
Example
my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
members(mydict, mylist) => 2
def members(dict,list):
    count=0
    for item in list:
        if bool(dict[item])==True:
            count=count+1
        else:
            count=count
    return count
```

William Li · Accepted Answer

@selcuk baran (https://teamtreehouse.com/selcukbaran) hi there.
The answer here might be simpler than you think.
python
def members(dic, ls):
    count = 0
    for item in ls:
        if item in dic:  # check if item is found in the dictionary keys
            count += 1   # if so, increment count by 1
    return count

I name my two function arguments dic & ls to avoid confusion with the build-in Python keywords dict & list. 
Lemme know if you need more help. Cheers

selcuk baran · Answer

if you have time could you please explain a little bit?

jason chan · Answer

py
def members (my_dict, my_list):
    count = 2
    for temp in my_list:
        if my_dict in my_list:
            count += 2
    else:
        return count

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selcuk baran

selcuk baran

I revised it however still a problem

3 Answers

William Li

William Li

jason chan

jason chan

selcuk baran

selcuk baran