Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial![](https://ecs-static.teamtreehouse.com/assets/views/marketing/shared/community-banner-white-47072046c51352fe6a69f5e691ff5700b28bb11d45197d7bdf066d9ea3f72d0c.webp)
![Dick Johnson](https://secure.gravatar.com/avatar/eaf9e5d17d171b838fbb84bfa4e92597?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Dick Johnson
379 PointsI used the toString method and it caused a compilation error. I concatenated the integer with a String value...it worked
I'm not asking for help im trying to fill out a bug report
2 Answers
![Kourosh Raeen](https://uploads.teamtreehouse.com/production/profile-photos/3971082/micro_TreehouseProfilePic.jpg)
Kourosh Raeen
23,733 PointsIt's not a bug. You cannot call toString() on a variable of type int. You could do one of the following:
String intAsString = Integer.toString(randomNumber);
or
String intAsString = String.valueOf(randomNumber);
or
String intAsString = randomNumber + "";
![Dick Johnson](https://secure.gravatar.com/avatar/eaf9e5d17d171b838fbb84bfa4e92597?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Dick Johnson
379 PointsThanks