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samuel bailey
6,911 Pointsillegal escape character???
public String[] getWords() { return = mBody.split("\s+"); }
2 Answers
deckey
14,630 PointsHi Samuel, interpreter is reading \s as an escape character, which does not exist.
What you need to do is tell it to ignore the backslash by adding one more, with \\s
Oh, and there is no = for return statements, good luck!
Seth Kroger
56,413 PointsBecause Java strings use \ as an escape sequence for special characters in strings every time you need to use a \ in a regex you need to double it: \