IOS Function parameters

Question

I'm lost needing some help, with function parameters in swift 3 IOS
```functions.swift
// Enter your code below
func getRemainder(ofValue : a, b value: Int){
 return(a%b) 
}
```

Jorge Solana · Accepted Answer

Hey Tywan,
You should first review the previous challenge videos and write down good notes of how to call properly to a function. You have there two big problems:
- 1st, the function parameters (the ones that are received between parenthesis). You first put the name and then the type, so it would be like this: "(a: Int, b: Int)". Then since we are asked to name them to be more specific, we add "value" and "divisor" before them.
- 2nd, since you're writing a return code, you need to specify the return type at the end of the function declaration like "-> Int"
This is the challenge solution, but try to understand and keep up the good work!
```swift
// Enter your code below
func getRemainder(value a: Int, divisor b: Int) -> Int {
  return a%b
}
let result = getRemainder(value: 10, divisor: 3)
```
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Tywan Claxton

Tywan Claxton

IOS Function parameters

1 Answer

Jorge Solana

Jorge Solana