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Python Python Basics (2015) Letter Game App Even or Odd Loop

Taebin You
Taebin You
4,786 Points
Posted by Taebin You
Taebin You
4,786 Points

Make a while loop that runs until start is falsey.

I just cannot understand why this would not work! Can someone please tell me why??

even.py 
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start > 0:
    randnumb = random.randint(1, 99)
    if even_odd(randnumb):
        print("{} is even.".format(randnumb))
    else: 
        print("{} is odd.".format(randnumb))
    start = start - 1

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! Actually, it does work! The problem here is that you aren't printing the exact string they are asking for. Challenges can be very strict about output/returned data. In this case, you've included a period/full stop on the strings. If I copy/paste your code in the challenge and then remove those, your code passes all three steps! Just delete the periods.

Hope this helps! :sparkles:

Taebin You
Taebin You
4,786 Points
Taebin You
Taebin You
4,786 Points

oh u r right lol