most_classes challenge

Question

I'm having difficulty passing the challenge.

any suggestions to guide me in the right direction is greatly appreciated

teachers.py

# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
def most_classes(dict):
    max_count=[0]
    for value in most_classes.values():
        if (value)> max_count:
            return(key)
        else:
            max_count.append(value)

Answer 1 · 2016-06-04T00:18:47Z

June 4, 2016 12:18am

You have a few issues here. Here's a few hints:

remember your argument is "dict" (most_classes is the name of the function!)
if you use values() on a dict you will get only values, but you need to find a name (key)
you won't need to build a list, you only need to remember who had the most so far
you won't want to return until the loop has checked everyone

If that doesn't get you going, you might want to review the Dictionary Iteration video .

Answer 2 · 2016-06-05T19:44:23Z

June 5, 2016 7:44pm

<p>
def most_classes(my_dict):
    count=0
    name=''
    max_count={}
    for name in my_dict:
        if len(my_dict[name])>count:
            count=len(my_dict[name])
            max_count.update([name])
            return max_count 
</p>

tried a different approach, any thoughts?

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Laknath Gunathilake

Laknath Gunathilake

most_classes challenge

2 Answers

Steven Parker

Steven Parker

Laknath Gunathilake

Laknath Gunathilake