My code is slightly different to what is shown, are there any disadvantages to the way I have solved it?

Hi -

I've completed the following code for this solution. It's slightly different, like I set my first variable as 0 instead of empty. Are there any distinct disadvantages to doing it like I have?

*/ let correctAnswers = false; console.log(correctAnswers);

let playerRank = 0; console.log(playerRank);

const main = document.querySelector('main');

let question1 = prompt('What is the capital of France?'); if (question1.toUpperCase() === 'PARIS') { correctAnswers = true; console.log(correctAnswers = 'You scored!'); playerRank = playerRank + 1; console.log(playerRank); } let question2 = prompt('What is the capital of the Spain?'); if (question2.toUpperCase() === 'MADRID') { correctAnswers = true; console.log(correctAnswers = 'You scored!'); playerRank = playerRank + 1; console.log(playerRank); } let question3 = prompt('What is the capital of Italy?'); if (question3.toUpperCase() === 'ROME') { correctAnswers = true; console.log(correctAnswers = 'You scored!'); playerRank = playerRank + 1; console.log(playerRank); } let question4 = prompt('What is the capital of Germany?'); if (question4.toUpperCase() === 'BERLIN') { correctAnswers = true; console.log(correctAnswers = 'You scored!'); playerRank = playerRank + 1; console.log(playerRank); } let question5 = prompt('What is the capital of the United States?'); if (question5.toUpperCase() === 'WASHINGTON') { correctAnswer = true; console.log(correctAnswers = 'You scored!'); playerRank = playerRank + 1; console.log(playerRank); }

let finalRank = '';

if (playerRank === 0) { finalRank = 'No crown'; console.log(finalRank); } else if (playerRank > 0 && playerRank <= 2) { finalRank = 'Bronze'; console.log(finalRank); } else if (playerRank >= 3 && playerRank <= 4) { finalRank = 'Silver'; console.log(finalRank); } else if (playerRank === 5) { finalRank = 'Gold'; console.log(finalRank); }

main.innerHTML = <h2>You got ${playerRank} out of 5!</h2> <p>Crown earned: ${finalRank}</p> ;