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JavaScript jQuery Basics (2014) Creating a Password Confirmation Form Perform: Part 2

Mayur Pande
PLUS
Mayur Pande
Courses Plus Student 11,711 Points
Posted by Mayur Pande
Mayur Pande
Courses Plus Student 11,711 Points

My code works so far but...

it when I clear the password form field, then hint stays there, I thought this line is supposed to make it hide;

//1) Hide hints 
$("form span").hide();

Here is my full app.js

//Problem: Hints are shown even form is valid
//Solution: Hide and show them at appropriate times
var $password = $('#password');
var $confirmPassword = $("#confirm_password");
//1) Hide hints 
$("form span").hide();

function passwordEvent() {

  //return val - which is a string - then check if length is greater than 8
  //2) Find out if password is valid
  if($password.val().length > 8){
    //2.1) Hide hint if valid
    $password.next().hide();

  }else{
    //2.2) else show hint
    $password.next().show();
  }

}

function confirmPasswordEvent(){
  //3.1) Find out if password and confirmation match
  if($password.val() === $confirmPassword.val()){
    //3.2) Hide hint if match
    $confirmPassword.next().hide();

  }else{
    //3.3) else show hint
    $confirmPassword.next().show();

  }
}

//When event happens on password input - events on particular input
$password.focus(passwordEvent).keyup(passwordEvent).focus(confirmPasswordEvent).keyup(confirmPasswordEvent);

//3) When event happens on confirmation input
$confirmPassword.focus(confirmPasswordEvent).keyup(confirmPasswordEvent);
Raymer Ramos
Raymer Ramos
7,683 Points

Hey Mayur Pande

//1) Hide hints $("form span").hide();

that line of code will only hide it at the beginning of the program, the reason it stays after you clear the password field is because the event handler keyup is being called on it when you release the backspace key, so since the empty field length is less than 8 the hint stays visible

if($password.val().length > 8){
    //2.1) Hide hint if valid
    $password.next().hide();

  }else{
    //2.2) else show hint
    $password.next().show();
  }