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PHP Build a Simple PHP Application Creating the Menu and Footer Variables

my syntax : $webname = "Shirts 4 mike"; is showing an error....?

Even my syntax is perfect it is showing an error...

$webname="Shirts 4 mike"; 
echo $webname;

1 Answer


The challenge is asking for you to ...assign the name of our website to a variable called "name".

Try changing $webname to $name so it becomes:


$name = "Shirts 4 Mike";
echo $name;


You'll also need to check your casing for Shirts 4 Mike.