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PHP Build a Simple PHP Application Creating the Menu and Footer Variables

Posted by Rajvansh Sharma
Rajvansh Sharma
333 Points

my syntax : $webname = "Shirts 4 mike"; is showing an error....?

Even my syntax is perfect it is showing an error...

variables.php 
<?php
$webname="Shirts 4 mike"; 
echo $webname;
?>

1 Answer

Rich Bagley
Rich Bagley
25,869 Points
Rich Bagley
Rich Bagley
25,869 Points

Hi,

The challenge is asking for you to ...assign the name of our website to a variable called "name".

Try changing $webname to $name so it becomes:

<?php

$name = "Shirts 4 Mike";
echo $name;

?>

You'll also need to check your casing for Shirts 4 Mike.

-Rich