Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Dimitrios Exarchos
893 Pointsneed some help
I think I am missing something here....
import random
start = 5
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
while start != True:
random_num = random.randint(1, 99)
if even_odd(random_num) == True:
print("{} is even").format(random_num)
else:
print("{} is odd").format(random_num)
start=start -1
1 Answer

Christopher Shaw
Python Web Development Techdegree Graduate 58,236 PointsYou have two mistakes.
- Your use of format, you have it outside the print parenthese.
print("{} is even".format(random_num))
- Your while condition. Start will be true until it equals 0, Below is the same as while == true
while start: