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![Jerle Norton](https://secure.gravatar.com/avatar/001eb57ad309068247ba6be817608965?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Jerle Norton
905 PointsNeed some help with the Membership objective.
https://teamtreehouse.com/library/python-collections/dictionaries/membership
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
1 Answer
![John Simmons](https://secure.gravatar.com/avatar/960718f4d9db2ef96f56cc0bd77855b9?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
John Simmons
1,247 Pointsdef members(dictionary, lst):
count = 0
for item in lst:
if item in dictionary:
count += 1
return count
def members(dictionary, lst):
member_count = [item for item in in lst if item in dictionary]
return len(member_count)
![Jerle Norton](https://secure.gravatar.com/avatar/001eb57ad309068247ba6be817608965?s=60&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Jerle Norton
905 PointsThanks John. I was really close but i see now what i was doing wrong.
jacinator
11,936 Pointsjacinator
11,936 PointsWhat code have you tried so far?