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JavaScript jQuery Basics (2014) Creating a Simple Drawing Application Perform: Part 2

Franklin Colbert
Franklin Colbert
4,868 Points
Posted by Franklin Colbert
Franklin Colbert
4,868 Points

#newColor span doesn't show up at all

I can't get the #newColor box to show up at all

// problem: no user interaction causes changes to the application
// solution: when user interacts, appropriate changes occur

var color = $('.selected').css("background-color");

// when clicking on control list items (color selectors)
$(".controls li").click(function(){                       
// deselect siblings
  $(this).siblings().removeClass("selected");
  // select color we just clicked
  $(this).addClass("selected");
  //cache current color
  $(this).css("background-color");
                        });

// when new color is pressed
$("#revealColorSelect").click(function(){
  // show color select or hide color select
  changeColor();
  $("#colorSelect").toggle();
});


// update the new color span
function changeColor() {
  var r = $("#red").val();
  var g = $("#green").val();
  var b = $("#blue").val();

  $("#newcolor").css("background-color", "rgb(" + r + "," + g + "," + b + ")");
};
// when color sliders change
$("input[type=range]").on("input", schangeColor);

// when add color is pressed
 // append color to the controls ul
 // select the new color


// on mouse events on the canvas
  // draw lines

1 Answer

LaVaughn Haynes
LaVaughn Haynes
12,397 Points
LaVaughn Haynes
LaVaughn Haynes
12,397 Points

you had some typos. javaScript is case sensitive

// update the new color span
function changeColor() {
  var r = $("#red").val();
  var g = $("#green").val();
  var b = $("#blue").val();

  //wrong case: newcolor should be newColor ******************
  //$("#newcolor").css("background-color", "rgb(" + r + "," + g + "," + b + ")");
  $("#newColor").css("background-color", "rgb(" + r + "," + g + "," + b + ")");
};
// when color sliders change
//bad code: also schangeColor is not a function ******************
//$("input[type=range]").on("input", schangeColor);
$("input[type=range]").on("change", changeColor);
Franklin Colbert
Franklin Colbert
4,868 Points
Franklin Colbert
Franklin Colbert
4,868 Points

thanks, I keep forgettin that lowerCamelcase !