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Start your free trialBoris Likhobabin
3,581 PointsNot exactly surrounding points! The results of this method also include the point itself.
If lets say we pass on to the method x:2, y:2 as an output we get point (2,2) as well which is the point that were not looking for as it is not the one surroundING but the one that is surroundED. I thought what we could do is take that point out of the array before the results are printed? however I can't find something which is the opposite of append.
Can you please tell me whether I am wright with my suggestion or did I not get what Pasan tried to accomplish with this method?
Thanks in advance By the way this is my first question that I ever post about coding (not just teamtreehouse) so I'm super excited about the answer!
1 Answer
Derick Derick
410 PointsYou can try this to get the output without the original point "(2,2)".
func surroundingPoints(withRange range: Int = 1) -> [Point] {
var results: [Point] = []
let originalPoint = Point(x: x, y: y)
for xCoordinate in (x-range)...(x+range){
for yCoordinate in (y-range)...(y+range) {
let coordinatePoint = Point(x: xCoordinate, y: yCoordinate)
if ((coordinatePoint.x == originalPoint.x) && (coordinatePoint.y == originalPoint.y)) {
} else {
results.append(coordinatePoint)
}
}
}
return results
}