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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Avery Uslaner
Avery Uslaner
15,099 Points

Not sure what's wrong with my even_odd script

Why does this not pass the challenge?

even.py 
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start not 0:
  numb = random.randint(1, 99)
  if even_odd(numb):
    print("{} is even".format(numb))
  else:
    print("{} is odd".format(numb))
  start -= 1

3 Answers

Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Hi Avery,

start not 0 is invalid syntax.

# You'd either need to do
while start > 0
# or
while start != 0
Avery Uslaner
Avery Uslaner
15,099 Points
Avery Uslaner
Avery Uslaner
15,099 Points

Ohhh ok. In times like these I wish I could actually see the error output. "Bummer, try again" isn't very helpful for spotting mistakes like this.

eirikvaa
eirikvaa
18,015 Points
eirikvaa
eirikvaa
18,015 Points

If you change

while start not 0:

to

while start > 0:

then you're good to go. It's just a syntax error. The rest of the code is super duper.