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Start your free trialGary Cardinale
Courses Plus Student 1,944 Pointspassing an attr value
I keep getting a syntax error for the following line $image.attr('src' 'imageLocation');
2 Answers
Michael Hulet
47,913 PointsYou need to put a comma between 'src'
and 'imageLocation'
. This code should work:
$image.attr('src', 'imageLocation');
Gary Cardinale
Courses Plus Student 1,944 PointsThanks, I took the quotes off imageLocation too. Works now