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PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

PHP code challenge - conditional "echo" per variable value

Code Challenge issue:

For: Challenge task 3 of 4

The message in the final echo command only makes sense if your favorite flavor is the same as mine. Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." (Remember to choose carefully between using a single equal sign and a double equal sign in the check.) Preview the code and, if you have a different flavor, make sure the message disappears.

This works:

<?php $flavor = "chocolate"; echo "<p>Your favorite flavor of ice cream is "; echo $flavor; echo ".</p>"; if ($flavor == "cookie dough") { echo "<p>Randy's favorite flavor is cookie dough, also! </p>"; }

?>

However, when I change the $flavor to = "cookie dough" - then I get the error msg:

"Oops! It looks like Task 3 is no longer passing.

I go to the task in question - I tried changing the == to =, but that didn't work.

What am I doing wrong here?

(i.e. If I need to add another "if" statement to "hide" the "Randy" echo, how do I do that? I didn't catch that in the video.)

3 Answers

Make sure you have echo ".</p>"; instead of echo "."; on the fifth line. It's picky about the output being exact.

Okay. I guess that made the difference. Thanks, Ben!

<?php $flavor="cream"; echo "<p>Your favorite flavor of ice cream is "; echo $flavor; echo ".</p>"; if ($flavor == "cookie dough") {echo "<p>Randy's favorite flavor is cookie dough, also!</p>";}

?>