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PHP Object-Oriented PHP Basics (Retired) Properties and Methods Mid-Course Challenge

Devin Scheu
Devin Scheu
66,191 Points

Php help

Question: Create a method on Fish named getInfo that takes no parameters and returns a string that includes the common_name, flavor, and record_weight for the fish. When called on $bass, getInfo might return "A Largemouth Bass is an Excellent flavored fish. The world record weight is 22 pounds 5 ounces."

Code:

fish.php
<?php

class Fish {
  public $common_name = "";
  public $flavor = "";
  public $record_weight = 0;

  function __construct($name, $flavor, $record) {
      $this->common_name = $name;
      $this->flavor = $flavor;
      $this->record_weight = $record;
  }

  public getInfo() {
    return "A {$common_name} is an {$flavor} fish. The world record weight is {$record_weight}";
  }
}

$bass = new Fish("Largemouth Bass", "Excellent", "22 pounds 5 ounces");

?>

4 Answers

Figured it out for you. I would say becareful when learning multiple languages at once. I have the same problem with syntax.

<?php

public function getInfo() {
        return "A". $this->common_name . " is an " . $this->flavor . 
          " flavored fish. The world record weight is " . $this->record_weight;

  }

?>

Ah. Of course. The $this-> part is what does it.

Good job, that one had me stumped.

You're missing the word "flavored" after the $flavored variable.

edit: Ryan Duchene answered the question

Devin Scheu
Devin Scheu
66,191 Points

Still not working for me

You forgot to add "flavored" in your return string, right after {$flavor}. :)

<?php

// ...

return "A {$common_name} is an {$flavor} flavored fish. The world record weight is {$record_weight}";

// ...