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JavaScript jQuery Basics (2014) Creating a Mobile Drop Down Menu Getting a value

Posted by Kohane Kagami
Kohane Kagami
12,390 Points

Please help me to solve this question.

I have no idea how to solve this problem. "https://teamtreehouse.com/library/jquery-basics/creating-a-mobile-drop-down-menu/getting-a-value"

Please help me.

Here is my code. What's wrong with it?

//Select the input for the title for blog post. var $titleInput = $("#title");

//Select the preview h1 tag var $previewTitle = $("#titlePreview");

// Every second update the preview var previewTimer = setInterval(updatePreview, 1000);

function updatePreview(){
//Get the user's input var titleValue; //Set the user input as the preview title. $titleInput=$previewTitle.text(titleValue).value(); }

js/app.js 
//Select the input for the title for blog post.
var $titleInput = $("#title");

//Select the preview h1 tag
var $previewTitle = $("#titlePreview");

// Every second update the preview
var previewTimer = setInterval(updatePreview, 1000);

function updatePreview(){  
  //Get the user's input
  var titleValue;
  //Set the user input as the preview title. 
  $titleInput=$previewTitle.text(titleValue).val();
}
index.html 
<!DOCTYPE html>
<html>
<head>
  <link rel="stylesheet" type="text/css" href="theme.css">
</head>
<body>
  <div id="form">
    <label for="title">Blog Post Title</label><input id="title" name="title" value="" placeholder="Enter your blog title here">
  </div>
  <div id="preview">
    <h1 id="titlePreview"></h1>
  </div>
  <script src="//code.jquery.com/jquery-1.11.0.min.js" type="text/javascript" charset="utf-8"></script>
  <script src="js/app.js" type="text/javascript" charset="utf-8"></script>
</body>
</html>
theme.css 
  #form {
    width: 45%;
    float: left;
  }
  #preview {
    width: 45%;
    float: right;
  }
  label {
    width: 20%;
    display: inline-block;
  }
  input {
    width: 70%;
  }

1 Answer

Anjali Pasupathy
Anjali Pasupathy
28,883 Points
Anjali Pasupathy
Anjali Pasupathy
28,883 Points

You're close! Rather than putting ".val()" at the end of the last line, you need to set "titleValue" to "$titleInput.val()":

//Get the user's input
  var titleValue = $titleInput.val();
  //Set the user input as the preview title. 
  $titleInput=$previewTitle.text(titleValue);

I hope this helps!

Kohane Kagami
Kohane Kagami
12,390 Points

Thank you very much!