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Java Java Basics Perfecting the Prototype String Equality

Shikha Agrawal
Shikha Agrawal
2,206 Points

Please tell me what I am missing here

Not sure what I am doing wrong. It looks fine to me.

Equality.java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
 if(thirdExample.equalsIgnoreCase(firstExample))
  console.printf("first and third are the same ignoring case");

2 Answers

Rob Bridges
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,467 Points

Hey there,

The above answer is correct, but to give you some visualization what he means by needing two else statements is below

String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equals(secondExample)) {
  console.printf("first is equal to second");
}
else  if (firstExample.equalsIgnoreCase(thirdExample)) {
  console.printf("first and third are the same ignoring case");
}

You need two "if' statements. One to check if the firstExample == secondExample and the other to check if firstExample == thirdExample, but this time with ignored casing. I am not sure how you pass step one with that code, but you do. Read both tasks again and add the missing if.