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JavaScript AJAX Basics (retiring) Programming AJAX Check for the correct ready state

programming ajax

Add a conditional statement inside the onreadystatechange event handler that tests to make sure the server has sent back its complete response.

app.js
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {

};
xhr.open('GET', 'sidebar.html');
xhr.send();
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>

1 Answer

Sergei Djomin
Sergei Djomin
18,675 Points
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if (xhr.readyState===4 && xhr.status===200) {
   ...
  }
};
xhr.open('GET', 'sidebar.html');
xhr.send();