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JavaScript Gulp Basics Improving your Gulp Task Pipelines The Build and Development Pipeline

Tom Checkley
Tom Checkley
25,165 Points
Posted by Tom Checkley
Tom Checkley
25,165 Points

putting files into a dev directory then utputting them to dist on build. I need to change my base can anyone explain?

I've followed this course all the way through and have used it in my own project and added to it. I want to be able to save all files in a dev directory that will output to dist on build, the following code works fine but it creates a directory in dist called dev which i don't want. I think I need to change the base but can't work out how. 

gulp.task("build", ['minifyScripts', 'compileSass', 'images'], function(){
    return gulp.src(["dev/css/build.css",
                                     "dev/js/app.min.js",
                                     'dev/css/*.css',
                                     'dev/index.html',
                                     'dev/img/**',
                                     'dev/fonts/**'],
                                    {base: './'})
                            .pipe(gulp.dest('dist'));
});
});

1 Answer

faraz
PLUS
faraz
Courses Plus Student 21,474 Points
faraz
faraz
Courses Plus Student 21,474 Points

Try setting your base to 'dev' -- that should prevent the dev directory from being created inside dist.