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iOS Intermediate Swift Extensions and Protocols Protocol Extensions

Posted by Brian Riviere
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Brian Riviere
iOS Development with Swift Techdegree Graduate 12,918 Points

Question not being accepted

I kept getting square protocol extension is not implemented correctly even those it is correct.

protocol Calculator { func square(_ value: Double) -> Double }

// Enter your code below extension Calculator { func square(_ value: Double) -> Double { return value.squareRoot() } }

protocols.swift 
protocol Calculator {
  func square(_ value: Double) -> Double
}

// Enter your code below
extension Calculator {
  func square(_ value: Double) -> Double {
     return value.squareRoot()
  }
}

1 Answer

Deysha Rivera
Deysha Rivera
5,088 Points
Deysha Rivera
Deysha Rivera
5,088 Points

You are not actually looking for the square root, you are trying to find the square. Your implementation should return value*value.

extension Calculator {
 func square(_ value: Double) -> Double {
     return (value * value)
  }
}