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Zee Liu
2,027 PointsRemove Duplicate
import random
x = ['a','b','c','d','e','f', 'g'] f = ['Jan','Feb','Mar','Apr','May','Jun']
shuffle1 = random.shuffle(x)
for i in x: print(f'{random.choice(x)}, {random.choice(f)}')
my goal is to print the list without duplicate each item in x appears at once, and each item in f appears at once as well. I tried, random.sample and random.choice, both pick duplicate items.
I really appreciate your help, I am really curious about how to do it.
1 Answer
Megan Amendola
Treehouse TeacherRandom will always choose a random item from the list so there is always the possibility of it choosing the same item more than once. In order to make sure you don't get the same item again, you can remove items as they are chosen. Then you will get a random item from the list and make sure it cannot be chosen again.
x = ['a','b','c','d','e','f', 'g']
rand_choice = random.choice(x)
x.remove(rand_choice)
Zee Liu
2,027 PointsZee Liu
2,027 PointsFor example: I am able to get the first column not duplicated. But the second column is still duplicate, when I do y.remove(d), it gives me an error
y.remove(d)
ValueError: list.remove(x): x not in list how can I delete the item that is already selected in list x and y?
import random
x = ['a','b','c','d','e','f', 'g'] y = ['z', 'n', 'm', 'l', 'o', 'p']
while len(x) > 0: z=[] z = random.choice(x) d = random.sample(y, 1) print(z, d) x.remove(z)