Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

STAGE 2 CHALLENGE TASK 3 OF 4

The message in the final echo command only makes sense if your favorite flavor is the same as mine. Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." (Remember to choose carefully between using a single equal sign and a double equal sign in the check.) Preview the code and, if you have a different flavor, make sure the message disappears.

index.php
<?php
$flavor = "vanilla";
echo "$flavor";
if ($flavor == "vanilla") {
  echo "Randy's favorite flavor is cookie dough, also!";
}
echo "<p>Your favorite flavor of ice cream is ";
echo "vanilla";
echo ".</p>";
echo "<p>Randy's favorite flavor is cookie dough, also!</p>";

?>

1 Answer

Anytime you want to echo out a variable value you will omit quotes.

<?php
$flavor = "vanilla";
echo $flavor; //we omitted the quotes here
echo "<p>Your favorite flavor of ice cream is ";
echo "vanilla";
echo ".</p>";

//we want to move the conditional down to keep the same dom structure and only out put this if flavor is the same
if($flavor == 'cookie dough') {
    echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
}