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JavaScript AJAX Basics (retiring) AJAX and APIs Create a callback function

stage 4 question 1-3

$(document).ready(function() { var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather'; var data = { q : "Portland,OR", units : "metric"

}); var showWeather = function(weatherReport); });

I tried this function inside the brackets and outside. It always give me error.

weather.js
$(document).ready(function() {
  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"

  });
   var showWeather = function(weatherReport);
});
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>What's the Weather Like?</title>
  <script src="jquery.js"></script>
  <script src="weather.js"></script>
</head>
<body>
  <div id="main">
    <h1>Current temperature: <span id="temperature"></span>&deg;</h1>
  </div>
</body>
</html>

1 Answer

Never mind figure it out. this code works fine :)

$(document).ready(function() {
  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"

  };
 var showWeather = function showWeather(weatherReport) {};
});