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iOS Swift Functions and Optionals Parameters and Tuples Tuples

Posted by David Yoon
David Yoon
581 Points

'String' is not convertible to '(greeting: String, language: String)' return language

I get this error. Is there any way I can resolve this??

swift_lint.swift:11:12: error: 'String' is not convertible to '(greeting: String, language: String)' return greeting ^ swift_lint.swift:12:12: error: 'String' is not convertible to '(greeting: String, language: String)' return language

tuples.swift 
func greeting(person: String) -> (greeting: String, language: String) {
    let language = "English"
    let greeting = "Hello \(person)"

    return greeting
    return language
}
Richard Robinson
Richard Robinson
5,373 Points

David,

Because you are returning a tuple, your return statement needs to be in compound form.

Try using this syntax to replace your two, separate return statements:

"return (greeting, language)"

David Yoon
David Yoon
581 Points

Thank you so much!

2 Answers

kjvswift93
kjvswift93
13,515 Points
kjvswift93
kjvswift93
13,515 Points

This is how your code should look:

func greeting(person: String) -> (greeting: String, language: String) {
    let language = "English"
    let greeting = "Hello \(person)"

   return (language, greeting)
}

You have an incorrect return statement. The compiler doesn't understand why you are making two separate return statements that do not match the return type for the greeting function.

Emily Zhao
Emily Zhao
2,581 Points
Emily Zhao
Emily Zhao
2,581 Points

Why did we have to identify greeting in (greeting: String) and language in (language: String) in line 1?

I rewatched the video and the instructor didn't talk about this. He has func searchNames (#name: String) -> (Bool, String).

Using the same logic, shouldn't it be func searchNames(#name: String) -> (found: Bool, found: String)?

Thanks in advance!