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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Hussein Amr
Hussein Amr
2,461 Points

stuck on the code challenge as always

any ideas on how i should proceed?

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(*args).lower():
    word = "I am a good kid am I not"
    word = list(word)
    for string in word:

1 Answer

Hey!

The python word = list(word) is returning a list of the chars in the variable word.

You should try the split() method. For example:

sentence = "My name is Eric"
words_in_sentence = sentence.split()
print words_in_sentence

This will print out ['My', 'name', 'is', 'Eric']

Hint: sentence.lower().split() will return ['my', 'name', 'is', 'eric']