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Java Java Basics Perfecting the Prototype String Equality

mohamadreza azadi
mohamadreza azadi
5,167 Points

syntax error

it's say :JavaTester.java:108: error: cannot find symbol if(firstExample.equal(secondExample)) ^ symbol: method equal(String) location: variable firstExample of type String 1 error
i dont know what's that error

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
  console.printf("first is equal to second");

1 Answer

james south
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,258 Points

the (a) proper method name is equals, not equal. also you are missing the curly braces around the body of the if statement. add an s to equal and the curly braces and it will pass.