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6,274 PointsSyntaxError: for letter in messy_list
Alright, my list is messy! Help me clean it up! First, start by moving the 1 from index 3 to index 0. Try to do this in a single step by using both .pop() and .insert(). It's OK if it takes you more than one step, though!
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
for letter in messy_list
if letter != 3:
messy_list.pop
else letter.insert(0)
1 Answer
Chris Freeman
Treehouse Moderator 68,457 PointsThe challenge is more straightforward than you're making it.
You're given the index of the item to pop (the 1 is at index 3) so no need to loop through to look for it.
item = messy_list.pop(3)
Then insert item back into list
messy_list.insert(item)
These two statements can be chained together into one. Can you figure out it can be done?
Post back if you need more help. Good luck!!!
Aananya Vyas
20,157 Pointsmessy_list.insert(0,messy_list.pop(3))
Thanks!
Alex Moats
4,535 PointsAlex Moats
4,535 PointsMake sure that when you are using .pop() you are supplying the index of the list. ie messy_list.pop(4) would remove the 'False' value from the 4 index position.
Also, when you are using .insert() you'll need to supply the index, and the thing you want to insert to the list.
ie messy_list.insert(0, "Thing") would insert the string "Thing" into the beginning of the list at 0 index position.