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JavaScript jQuery Basics (2014) Creating a Simple Lightbox Creating and Appending Detached DOM elements

Posted by Martin Guzman
Martin Guzman
11,573 Points

Take a moment to read the code in the app.js file. The code should display a modal or pop-over window (built with HTML).

Take a moment to read the code in the app.js file. The code should display a modal or pop-over window (built with HTML). In the modal window there should be a place for a message to display and a button to dismiss or close the modal. Check out how the code runs in the preview. There's something wrong. The dismiss button isn't showing in the modal. Can you fix it?

js/app.js 
//Create the Modal
var $modal = $("<div id='modal'></div>");

//Create a placeholder for text in the modal
var $placeHolder = $("<p id='placeHolder'></p>");
$modal.append($placeHolder);

//Create a button to dismiss modal and add it to modal
var $dismissButton = $("<button>Dismiss</button>");

//Hide modal when button is pressed
$dismissButton.click(function(){
  $modal.hide(300);
});

$("body").append($modal);

//A function to show a modal
function displayModal(message) {
  $placeHolder.text(message);
  $modal.show();
}

//Show an example modal
displayModal("Hello World!");
index.html 
<!DOCTYPE html>
<html>
<head>
    <link rel="stylesheet" href="css/style.css" type="text/css" media="screen" title="no title" charset="utf-8">
    <title>Modal Example</title>
</head>
<body>
    <h1>Modal Example Page</h1>

    <script src="//code.jquery.com/jquery-1.11.0.min.js" type="text/javascript" charset="utf-8"></script>
    <script src="js/app.js" type="text/javascript" charset="utf-8"></script>
</body>
</html>

2 Answers

Henrik Christensen
seal-mask
.a{fill-rule:evenodd;}techdegree
Henrik Christensen
Python Web Development Techdegree Student 38,322 Points
Henrik Christensen
.a{fill-rule:evenodd;}techdegree
Henrik Christensen
Python Web Development Techdegree Student 38,322 Points 
//Create a button to dismiss modal and add it to modal
var $dismissButton = $("<button>Dismiss</button>");
$modal.append($dismissButton);

This should pass the test

Jaime Sánchez Blanco
Jaime Sánchez Blanco
16,894 Points
Jaime Sánchez Blanco
Jaime Sánchez Blanco
16,894 Points

Hi Martin. this worked for me:

var $dismissButton = $("<button>Dismiss</button>");

$dismissButton.appendTo($modal);