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JavaScript

Posted by Martín Javier Del Percio
Martín Javier Del Percio
2,663 Points

the example don't work

let html = ''; const randomValue = () => Math.floor(Math.random() * 256);

function randomRGB() { const color = rgb( ${randomValue()}, ${randomValue()}, ${randomValue()} ); return color;
}

for (let i=1; i<=64; i++) { html += <div style="background-color: ${randomRGB()}">${i}</div>;
}

document.querySelector('main').innerHTML = html;

Cameron Childres
Cameron Childres
11,818 Points
Cameron Childres
Cameron Childres
11,818 Points

Hi Martín,

If you click on "markdown cheatsheet" below the comment box you'll find ways to format your code so we can read it easier, otherwise characters might be dropped like your backticks on the template literal. Here is your code with formatting:

let html = ''; 
const randomValue = () => Math.floor(Math.random() * 256);

function randomRGB() { 
  const color = `rgb( ${randomValue()}, ${randomValue()}, ${randomValue()} )`; 
  return color;
}

for (let i=1; i<=64; i++) { 
  html += `<div style="background-color: ${randomRGB()}">${i}</div>`;
}

document.querySelector('main').innerHTML = html;

This code runs for me just fine, producing 64 numbered divs with randomized background colors on each refresh.

If you let us know more details about the issue you're having that would help. Are you getting any console errors? Is anything happening at all? Also worth checking that your HTML has a <main> element and that the script source is loaded after it.

1 Answer

Steven Parker
Steven Parker
231,007 Points
Steven Parker
Steven Parker
231,007 Points

Assuming your code contains the backtick characters where shown in Cameron's example, the code itself seems to be good.

However, for this code to work there must also be an HTML code component that contains a "<main>" element.