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Android Build an Interactive Story App (Retired) Finishing the User Interface Using a Model in the Controller

The LandingActivity interacts with the Spaceship model object we created. Start by setting mSpaceship to a new Spacesh

May i get help on how to solve this.Been stuck for daez.

LandingActivity.java
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class LandingActivity extends Activity {

    public Button mThrustButton;
    public TextView mTypeLabel;
    public EditText mPassengersField;

    public Spaceship mSpaceship;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_landing);

        mThrustButton = (Button)findViewById(R.id.thrustButton);
        mTypeLabel = (TextView)findViewById(R.id.typeTextView);
        mPassengersField = (EditText)findViewById(R.id.passengersEditText);

        // Add your code here!
    }
}
Spaceship.java
public class Spaceship {
    private String mType;
    private int mNumPassengers = 0;

    public String getType() {
      return mType;
    }

    public void setType(String type) {
      mType = type;
    }

    public int getNumPassengers() {
      return mNumPassengers;
    }

    public void setNumPassengers(int numPassengers) {
      mNumPassengers = numPassengers;
    }

    public Spaceship() {
      mType = "SHUTTLE";
    }

    public Spaceship(String type) {
      mType = type;
    }
  mSpaceship = new Spaceship("FIREFLY");
}

1 Answer

For the first task you have to set mSpaceship to a new Spaceship object and pass in "FIREFLY" as the parameter since it has been defined in the custom constructor in Spaceship.java:

    public Spaceship(String type) {
      mType = type;
    }

So the line of code will be:

        // Add your code here!
        mSpaceship = new Spaceship("FIREFLY");

Hope you have no trouble with the other exercises.