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Python Python Collections (2016, retired 2019) Dictionaries Word Count

This works in my IDE, but not in Workspaces...

Why won't this compile for wordcount.py?

def word_count(sentence): new_sentence = sentence.lower().split(" ") new_dict = {} for word in new_sentence: new_dict[word] = new_sentence.count(word) return new_dict

Please and thank you!!!

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(sentence):
    new_sentence = sentence.lower().split(" ")
    new_dict = {}
    for word in new_sentence:
        new_dict[word] = new_sentence.count(word)
    return new_dict

1 Answer

Christian Mangeng
Christian Mangeng
15,970 Points

Hi Jose,

it works if you do not explicitly define a space in the split command. Just use .split() instead of .split(" ").

Oh man, thank you so much!!!