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iOS Functions in Swift Functions in Swift Recap: Functions

Arturo Carrasco Jr
Arturo Carrasco Jr
3,021 Points

What am I doing wrong?!

Challenge Task 3 of 3

Sweet, we have a function! In this task, all you have to do is call the function and pass in a value of 24.0 degrees. Assign the result of the function to a constant named fahrenheitTemp.

(Here's what I wrote)

func temperatureInFahrenheit ( temperature: Double) -> Double{ let fahrenheitTemp = (temperature * 9)/5 + 32 return (fahrenheitTemp)} let fahrenheitTemp = temperatureInFahrenheit(24.0)

functions.swift
// Enter your code below

func temperatureInFahrenheit ( temperature: Double) -> Double{ let fahrenheitTemp = (temperature * 9)/5 + 32
return (fahrenheitTemp)}
let fahrenheitTemp = temperatureInFahrenheit(24.0)
Rafael Reis
Rafael Reis
14,931 Points

You don't have to declare the variable and then return it, like this: return (temperature * 9)/5 + 32

Arturo Carrasco Jr
Arturo Carrasco Jr
3,021 Points

func temperatureInFahrenheit (temperature: Double) -> Double { return (temperature * 9)/5 + 32 } let fahrenheitTemp = temperatureInFahrenheit(24.0)

I change it to this like you said but then this error comes out:

swift_lint.swift:9:46: error: missing argument label 'temperature:' in call let fahrenheitTemp = temperatureInFahrenheit(24.0) ^ temperature:

Arturo Carrasco Jr
Arturo Carrasco Jr
3,021 Points

Never mind I finally figured it out /.-

func temperatureInFahrenheit ( temperature: Double) -> Double{ let fahrenheitTemp = (temperature * 9)/5 + 32 return (fahrenheitTemp)} let fahrenheitTemp = temperatureInFahrenheit(temperature: 24.0)